Question

The sum of three consecutive numbers is 576. What is the 2nd number?

Answer 1

Answer:

Sum of three consecutive number is 576.

Let first number be X

Let second number be X+1

Let third number be X+ 2

So sum of three numbers which mean:-

=X+X+1+X+2=576

=3X+3=576

$3x = 576 - 3$

$3x = 573$

$x = \frac{573}{3}$

$x = 191$

So first number be(X) =191

so second number be (X+1) = 191 +1=192

so third number be (X + 2)=191+2=193

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Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given 3 consecutive numbers
• The sum of numbers is 576

To Find:

• We have to Find the second number

Solution:

Let the three consecutive numbers be

x , ( x + 1 ) , ( x + 2 )

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$\underline{\large\mathfrak\orange{According \: to \: the \: Question:}}$

Sum of numbers is 576

$\hookrightarrow \boxed{\sf{Sum \: of \: numbers = 576}}$

$\hookrightarrow \sf{ \: x + x + 1 + x + 2 = 576}$

$\hookrightarrow \sf{ \: 3x + 3 = 576}$

$\hookrightarrow \sf{\: 3x = 573}$

$\hookrightarrow \sf{\: x = \dfrac{573}{3}}$

$\hookrightarrow \sf{\: x = \cancel{\dfrac{573}{3}}}$

$\hookrightarrow \sf{\: x = 191}$

________________________________

$\underline{\large\mathfrak\purple{Finding \: the \: values}}$

$\implies \sf{First \: Number = x}$

$\implies \sf{191}$

$\implies \sf{Second \: Number = x + 1}$

$\implies \sf{191 + 1}$

$\implies \sf{192}$

$\implies \sf{Third \: Number = x + 2}$

$\implies \sf{191 + 2}$

$\implies \sf{193}$

________________________________

$\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}$

$\large\boxed{\mathfrak\red{Second \: Number = 192 }}$

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$\huge\mathfrak\green{Verification:}$

$\boxed{\sf{Sum = 191 + 192 + 193 = 576 }}$

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