Question

the sum of three consecutive odd intergars is -219 find the integars

Answer 1

Let one number be x.

Therefore, the consecutive odd integers are x, x + 2 and x + 4 (Since the difference between 2 odd numbers is 2)

x + x + 2 + x + 4 = -219

3x + 6 = -219

3x = -219 - 6

3x = -225

x = -225/3

x = -75

Therefore the integers are:

x = -75

x + 2 = -75 + 2 = -73

x + 4 = -75 + 4 = -71

Hope it helps :)

Answer 2

Solution :-

Let,
The first odd integer be:x

Then the second odd integer is:-
x+2

Then the third odd integer is:-
x+2+2=x+4

Sum of three consecutive odd numbers = -219

A/q

(x)+(x+2)+(x+4)= - 219
3x+6= -219
3x= -219 -6
3x= -225
x= -75
now

The first integer is: x= -75

the second integer is: x+2=19+2 = 73

the third integer is: x+4=19+4= -71

Hope it helps you