The sum of three consecutive odd natural numbers is 105 .find the largest of the threenumbers.Ans-37
Answers
Answered by
1
Let first odd number be x.
2nd odd number = x+2
3rd odd number = x+4
x+x+2+x+4= 105
3x=99
x=33
Largest odd number = x+4 = 37
2nd odd number = x+2
3rd odd number = x+4
x+x+2+x+4= 105
3x=99
x=33
Largest odd number = x+4 = 37
Answered by
0
Answer:
33,35,37
Explanation:
First of all lets say the unknown numbers are
x
−
2
,
x
and
x
+
2
.
We can represent it like this because the question says that they are consecutive odd numbers, and by definition they will differ by 2 each time
By summing these terms together, we can solve for
x
:
105
=
x
−
2
+
x
+
x
+
2
105
=
3
x
x
=
35
Now that we have
x
, we can say the the consecutive odd numbers are
35
−
2
,
35
and
35
+
2=37
, which are 33,35,37
Hope it helps plz mark as brainliest
33,35,37
Explanation:
First of all lets say the unknown numbers are
x
−
2
,
x
and
x
+
2
.
We can represent it like this because the question says that they are consecutive odd numbers, and by definition they will differ by 2 each time
By summing these terms together, we can solve for
x
:
105
=
x
−
2
+
x
+
x
+
2
105
=
3
x
x
=
35
Now that we have
x
, we can say the the consecutive odd numbers are
35
−
2
,
35
and
35
+
2=37
, which are 33,35,37
Hope it helps plz mark as brainliest
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