the sum of three Consecutive odd nos. is 60 find the no. that is 18 more than the second no.
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Answer:
Step-by-step explanation:
Let the three nos be a, b, and c
Since they are odd and consecutive,
b= a+2
And c=a+ 4
a+b+c=60
a+a+2+a+4 =60
a= 18
b=20
c=22
The no that is 18 more than b is 20 + 18 = 38
Hope this helps
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