Math, asked by benerdauru98, 1 year ago

The sum of three consecutive odd number is equal to thirteen more than two times the largest largest number. Let the first odd number be 'n'.
a) write the equation of the problem
b) solve for 'n' to find the first number
c) what are the values of the second and the third odd numbers?
d) show that that equation is true

Answers

Answered by paidilokesh
7

Step-by-step explanation:

if first odd number is 'n',

then,the consecutive odd numbers are n,n+2,n+4.

given,

sum of three consecutive odd numbers is equal to

thirteen more than two times the largest number.

i.e,

3n+6=13+2(n+4)

3n+6=2n+21

n=15

n+2=17

n+4=19

therefore , three consecutive numbers are 15,17,19

mark as Brainliest answer.... please......

Answered by kanodboiid
1

Step-by-step explanation:

a) write the equation of the problem

b) solve for 'n' to find the first number

c) what are the values of the second and the third odd numbers?

d) show that the equation is true

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