Question

The sum of three consecutive odd numbers exceeds the smallest by 36. The numbers are__, __ and__.
please don't give the wrong answer .. ..​

Answer 1

Step-by-step explanation:

hope it helps you thankyou

Answer 2

Let x be an odd number.
Then the consecutive odd numbers are:
x, x + 2, x + 4

Also the sum of these three exceeds the smallest odd number by 36, which means the smallest odd number is x and exceeds by 36 means x + 36.
So,

x + x + 2 + x + 4 = x + 36
3x + 6 = x + 36

Re arranging the equation to group them with like terms

3x - x = 36 - 6
2x = 30
x = 15

So the three consecutive numbers are:
x = 15
x + 2 = 17
x + 4 = 19

The three consecutive odd numbers are 15, 17 and 19