the sum of three consecutive odd numbers is 129. what are the numbers
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its the correct answer
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rishabh68:
gud
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Here is your solution
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers =129
A/q
(x)+(x+2)+(x+4)=129
3x+6=129
3x=129-6
3x=123
x=41
now
The first integer is: x=41
the second integer is: x+2=41+2 = 43
the third integer is: x+4=41+4=45
Hope it helps you
Let,
The first odd integer be:x
Then the second odd integer is:-
x+2
Then the third odd integer is:-
x+2+2=x+4
Sum of three consecutive odd numbers =129
A/q
(x)+(x+2)+(x+4)=129
3x+6=129
3x=129-6
3x=123
x=41
now
The first integer is: x=41
the second integer is: x+2=41+2 = 43
the third integer is: x+4=41+4=45
Hope it helps you
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