The sum of three consecutive odd numbers is 39. Find the largest number?
Answers
Step-by-step explanation:
Let the three consecutive numbers be a,a+1 and a+2.
Now it is given that the sum of these consecutive numbers is 39.
Hence, adding them and equating it to 39 we get:-
⇒a+a+1+a+2=39
Simplifying it we get:-
⇒3a+3=39
Solving it further we get:-
⇒3a=36
Now solving for the value of a we get:-
⇒a=363
On dividing we get:-
⇒a=12
Hence, the first number is 12.
Now putting the value of a in other two numbers we get:-
⇒a+1=12+1
Simplifying it we get:-
⇒a+1=13
Hence, the second number is 13.
Now putting the value of a in the third number we get:-
⇒a+2=12+2
Simplifying it we get:-
⇒a+2=14
Hence, the third number is 14.
Therefore, the three consecutive numbers are 12, 13 and 14.
Answer: 15
Step-by-step explanation:
Let first odd number be y.
y
Next odd number should be two more than the previous value. So,
y + 2
Next odd number should be two more than the previous value. So,
y + 2 + 2
= y+4
As per the question it is stated that the sum of these consecutive odd numbers is 39.
y + y+2 + y+4 = 39
3y +6 =39
3y+6-6=39-6
3y = 33
3y/3= 33/3
y=11
So, the first number is 11
So, the two consecutive odd numbers that comes after 11 are,
13 and 15.
So, the largest number is 15
Hope it was understandable.
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