Question

The sum of three consecutive positive even
integers is 9o. Find the numbers.​

Answer 1

Let,

The three consecutive integer = x, x+ 1 , x+ 2

x, x+ 1 , x+2 = 90

x + x + 1 + x+ 2 = 90

3x + 3 = 90

3x = 90 - 3

3x = 87

x = 87 / 3

x = 29

So,

The three consecutive integer

x

= 29

x+ 1

29 + 1

= 30

x+ 2

29 + 2

= 31

Answer 2

$\\ \large✠ \rm \underline{ \: Required \: Question :- }$

★ The sum of three consecutive positive even integers is 90. Find the numbers.

$\\ \large✠ \rm \underline{ \: Answer :- }$

$\\ \sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \longrightarrow \: 29 ,30 \: and \: 31$

$\\ \large✠ \rm \underline{ \: Solution :- }$

$\\ \: \: \sf \: \: \: \: \: Let , \: the \: three \: consecutive \: positive \: integers \:$

$\sf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: be \: x , (x + 1) \: and \: (x + 2)$

$\\ \\ \sf\: Now, \: According \: to \: the \: question$

The sum of three consecutive positive even

integers is 90.

$\\ \\ \sf \: \: \therefore \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x + x + 1 + x + 2 \: = \: 90$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \: \: x + x + x + 1 + 2 = 90$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \: \: 3x + 3 = 90$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \: \: 3x = 90 - 3$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \: \: 3x = 87$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \: \: x = \frac{87}{3}$

$\\ \\ \: \: \sf \: \: \: \: \: \: \: \: \: \:➝ \: \underline {\boxed{ \orange{ \tt \: x = 29}}}$

$\\ \sf \: \: Therefore,$

$\\ \\ \sf \: \: \: \: \: \: † \: The \: value \: of \: x = 1st \: number = 29 \:$

$\\ \\ \sf \: \: \: \: \: \: † \: The \: value \: of \: (x + 1) = 2nd \: number = 29 + 1 = 30\:$

$\\ \\ \sf \: \: \: \: \: \: † \: The \: value \: of \: (x +21) = 3rd \: number = 29 + 2 = 31\:$

$\\ \\ \sf \: ✧: \: \underline{ \: \: The \: consecutive \: positive \: integers \: are \: 29, 30 \: and \: 31 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \underline{ \sf \: respectively \: whose \: some \: is \: 90.}$