Question

The sum of three consecutive positive integers is 39 . Find these integer

Answer 1

Let the numbers be x, x+1,x+2
So, x+x+1+x+2=39
=3x=39
=x=39/3
=x=13
So, the numbers will be x=13
X+1=13+1=14
X+2=13+2=15

Answer 2

Answer:

The three consecutive positive integers are 12, 13 and 14

Step-by-step explanation:

Given:

Sum of 3 consecutive positive integers = 39

Find:

The three consecutive integers

Solution:

Let the first integer = $x$

As the integers are consecutive, the second integer = $x+1$

Third integer = $x+2$

Given that,

Sum of the integers = 39

⇒ $x+(x+1)+(x+2) = 39$

⇒ $3x+3 = 39$

⇒ $3x = 39-3$

⇒ $3x = 36$

⇒ $x=\frac{36}{3}$

⇒ $x =12$

That is, the integers are $x, \ x+1, \ x+2$

⇒ $12, \ 12+1, \ 12+2$

⇒ $12, \ 13, \ 14$

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