Question

the sum of three consecutive positive integers is 48 find the integers

Answer 1

let first consecutive positive integer be 'x'
". second ". ". ". ". ". '1x'
". third. ". ". ". ". ". '2x'
equation= x + 1x + 2x = 48
4x= 48
x= 48 ÷ 4
x= 12
hence, 1number= 12
2nd number= 12
3rd number= 24

Answer 2

Let the numbers be x, (x + 1) and (x + 2)

x + (x + 1) + (x + 2) = 48

3x + 3 = 48

3x = 48 - 3

3x = 45

x = 45/3

x = 15

So, the first number is 15

For finding 2nd and 3rd number

15 + 1

= 16

15 + 2

= 17

So, the second number is 16

And the third number is 17