the sum of three consecutive terms of an A.P. is 21 and their product is 280.find the A.P.
Attachments:
Shardul27:
If you like my answer Please mark it as brainliest And Be my follower if possible.
thanks
Answers
Answered by
2
10,7,4 is the required a.p
Answered by
12
a1 + a2 + a3 = 21
a1 x a2 x a3 = 280
Let the first term and second term and third term respectively be a - d, a, a+d.
=>a - d+a+a+d = 21
=>3a = 21
=>a = 7.
Given,
(a - d) a(a+d) = 280
=>a²-d²=280÷7
=>-d²=40-7²
=>-d²=-9
=>d = ±3.
Two A. Ps are:-
..10,7,4.. and. ..4,7,10...
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
a1 x a2 x a3 = 280
Let the first term and second term and third term respectively be a - d, a, a+d.
=>a - d+a+a+d = 21
=>3a = 21
=>a = 7.
Given,
(a - d) a(a+d) = 280
=>a²-d²=280÷7
=>-d²=40-7²
=>-d²=-9
=>d = ±3.
Two A. Ps are:-
..10,7,4.. and. ..4,7,10...
Hope this will help you.
If you like my answer
Please mark it as brainliest
And
Be my follower if possible.
thankz
If you like my answer Please mark it as brainliest And Be my follower if possible.
Similar questions