Question

The sum of three consecutive terms that are in A.P. is 27 and their product is 288.
Find the three terms.
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Answer 1

your ans is 2,9,16

2+9+16=27

2×9×16=288

Answer 2

Here is your answer...

Let the three terms of AP be..

a - d , a & a + d

then according to question....

a - d + a + a + d = 27

3a = 27

a = 9

Now , it is given that their product is ...

(a - d)(a)(a + d) = 288

a(a^2 - d^2) = 288.........(1)

now place the value of a in equation 1

9(9^2 - d^2 ) = 288

9^2 - d^2 = 288/9

81 - d^2 = 32

d^2 = 81 - 32

d^2 = 49

d = 7

then the three terms of the AP will be

a - d = 9 - 7 = 2

a = 9

a + d = 9 + 7 = 16

hence the three terms are 2 , 9 , 16

hope this will help you...

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