the sum of three consequtive multiples of 3 is 333.find the multiples
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x,x+1,x+2=333
3x+3=333
3x=330
x=110
3x+3=333
3x=330
x=110
Anonymous:
its consecutive multiples so x.x+3. and x+6 should come isn't it?
yaar answer wrong ha
Answered by
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let the three multiples be a-d, a and a+d
d = 3 ....( they are consecutive multiples)
ATQ
a-d+a+a+d = 333
3a= 333
a=111
therefore the multiples are 108, 111 and 114.
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d = 3 ....( they are consecutive multiples)
ATQ
a-d+a+a+d = 333
3a= 333
a=111
therefore the multiples are 108, 111 and 114.
Don't forget to thank me!
Have a nice day....
bhai thora answer detail ma batana
kyuni yeh consecutive terms hai
to inka common difference same hoga yani 3 - given
to inko let karlo
okkk
yeh thora technical yad karna padega
thanks
no prob.
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