Question

the sum of three conservative even natural numbers is 78. Find the greatest of these numbers

Answer 1

Let the number be a, a + 2, a + 4

According to question,

a + a + 2 + a + 4 = 78

=> 3a + 6 = 78

=> 3a = 72

=> a = 24

First number = 24

Second number = 26

Third number = 28

Answer 2

$\text{Your answer !!}$

$\textbf {Sum of three conservative even natural numbers = 78}$

$\text {So, let the first number = x}$

$\text {let the second one = x + 2}$

$\text {let the third one = x + 4}$

$= > x +( x + 2) + (x + 4) = 78 \\ \\ = > x + x + 2 + x + 4 = 78 \\ \\ = > 3x + 6 = 78 \\ \\ = > 3x = 78 - 6 \\ \\ = > 3x = 72 \\ \\ = > x = \frac{72}{3} \\ \\ = > x = 24$

$\text {First number = x = 24}$

$\text {Second number = x + 2 = 24 + 2 = 26}$

$\text {Third number = x + 4 = 24 + 4 = 28}$

$\textbf {Third one is the greatest !!}$

$\text {Thanks !! }$