Question

The sum of three no. is 98.The ratio of the first to second is 2/3 and the ratio of the second to third is 5/8. Find the second number.

Answer 1

Given a+b+C =98
a/b =2/3
a=2/3b

b/C =5/8
C =8/5b

a+b+C =98
(2/3+1+8/5)b =98
(49/15)×b =98
b=(98×15)/49
b=2×15
b=30
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Answer 2

Answer:

Step-by-step explanation:

Solution:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer: (c)