The sum of three number ap is 27 and product 405 .find the common difference .
Answers
Answered by
2
Answer:
Let the numbers be a - d, a, a + d which are in AP.
(a - d) + (a) + (a + d) = 27 .........(1)
(a - d)(a)(a + d) = 405 ..........(2)
(1) => 3a = 27
a = 9
(2) => (a2 - d2)(a) = 405
[(9)2 - d2] (9) = 405
(81 - d2) (9) = 405
729 - 9d2 = 405
9d2 = 729 - 405
9d2 = 324
d2 = 36
d = 6
Now, substitute the values in the 1st equation.
(a-d) = 9 - 6 = 3
a = 9
(a+d) = 9 + 6 = 15
Hence the numbers are 3, 9 and 15.
Verification;
(1) => (a-d) + (a) + (a+d) = 27
3 + 9 + 15 = 27
27 = 27
(2) = > (a-d)(a)(a+d) = 405
(3)(9)(15) = 405
405 = 405
Step-by-step explanation:
PkPrajapati:
yes
plzz
ok
mark as brianliest
pkp
ok by talk u later
mark as brianliest
aree kar to de
pk
ekk kam nhi kar sakta yarr
Similar questions