Question

the sum of three number is 32000.one of them is 10000 more than the greatest 3 digit number and the other is 100 more than the smallest 4 digit number. find the three numbers​

Answer 1

Answer:

The three numbers are,

10999, 1100, 19901

(1) first number

greatest three digit number = 999

10000+999 = 10999

(2) second number

smallest four digit number = 1000

1000+100 = 1100

(3) third number

summation = 32000

10999+1100+X = 32000

12099+X = 32000

X = 32000-12099

X = 19901