The sum of three number is 98. If the ratio of the first to the second is 2:3 and that of the second to the third is 5:8 then the second number is
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Let the three numbers be x, y, z.
x/y = 2/3 => 3x=2y => y =3/2x
y/z = 5/8 => 8y= 5z .
8(3/2x)= 5z .
12x = 5z .
z = 12/5x .
x + y + z = 98
x + 3/2x + 12/5 x = 98
10x+15x+24x / 10 = 98
49 x /10 = 98
49 x = 980
x = 20 .
Now, y = 3/2(20)=30
z = 12/5* (20) = 48 .
Therefore, The second number is 30
x/y = 2/3 => 3x=2y => y =3/2x
y/z = 5/8 => 8y= 5z .
8(3/2x)= 5z .
12x = 5z .
z = 12/5x .
x + y + z = 98
x + 3/2x + 12/5 x = 98
10x+15x+24x / 10 = 98
49 x /10 = 98
49 x = 980
x = 20 .
Now, y = 3/2(20)=30
z = 12/5* (20) = 48 .
Therefore, The second number is 30
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Answer:
Step-by-step explanation:
Solution:
Let the three numbers be x, y and z.
Sum of the numbers is 98.
x + y + z = 98………………(i)
The ratio of the first to the second is 2/3.
x/y = 2/3.
x = 2/3 × y.
x = 2y/3.
The ratio of the second to the third is 5/8.
y/z = 5/8.
z/y = 8/5.
z = 8/5 × y.
z = 8y/5.
Put the value of x = 2y/3 and z = 8y/5 in (i).
2y/3 + y + 8y/5 = 98
49y/15 = 98.
49y = 98 × 15.
49y = 1470.
y = 1470/49.
y = 30 .
Therefore, the second number is 30.
Answer: (c)
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