the sum of three numbers in a.p is 3 and their product is -35 .find the number
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Answered by
145
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Answered by
56
Let the terms be A-D,A,A+D
A/Q,
A-D+A+A+D = 3
3A = 3
A = 3/3 = 1
Again,
(A-D)(A)(A+D) = -35
A(A²-D²) = -35
1(1²-D²) = -35
D² = -35-1
D² = -36
D = ✓-36 = -6
HENCE,
REQUIRED NUMBERS ARE -5,1,-7
A/Q,
A-D+A+A+D = 3
3A = 3
A = 3/3 = 1
Again,
(A-D)(A)(A+D) = -35
A(A²-D²) = -35
1(1²-D²) = -35
D² = -35-1
D² = -36
D = ✓-36 = -6
HENCE,
REQUIRED NUMBERS ARE -5,1,-7
thank you
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