Question

The sum of three numbers in an Arithmetic Progression is 12 and their product is 48.Find those numbers.​

Answer 1

let the three numbers be :

a+d , a , a-d

given the sum is 12 so add the numbers

3a = 12

a = 4 ( therefore the first number of the ap is 4)

(a+d)(a)(a-d) = 48 ( we take a to the left hand side it becomes division)

(a2 - d2) = 48/4

(42 - d2) = 12

16 - d2 = 12

-d2 = -4

d= 2

therefore the numbers are 2,4,6.

Answer 2

Answer:

4 is your answer

Step-by-step explanation:

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