Question

The sum of three numbers in ap is 27 and the sum of their squares is293 then find the ap?

Answer 1

Hope this helps you



PLEASE MARK IT AS BRANLIEST ANSWER PLS

Answer 2

Answer:

The required AP is 4, 9, 14, 19,....

Step-by-step explanation:

Let the three numbers are (a-d), a, a+d.

The sum of three numbers in AP is 27.

$(a-d)+a+(a+d)=27$

$3a=27$

$a=9$

The sum of those  three numbers squares is 293.

$(a-d)^2+a^2+(a+d)^2=293$

$a^2-2ad+d^2+a^2+a^2+2ad+d^2=293$

$3a^2+2d^2=293$

$3(9)^2+2d^2=293$               (a=9)

$243+2d^2=293$

$d^2=25$

$d=5$

The common difference is 5. The AP is defined as

$a-d,a,a+2d,a+3d,...$

$4, 9, 14, 19,...$

Therefore the required AP is 4, 9, 14, 19,....