Question

the sum of three numbers in AP is -3 and their product is 8 , find the numbers
pls answer me guys pls​

Answer 1

Answer:

Solution :-

Let the number are x−y,x,x+y

Sum =−3

⇒x−y+3x+x+y=−3

⇒3x=−3

⇒x=−1

Now product =8

⇒(x−y)(x)(x+y)=8

Substituting x=−1

we get (−1−y)(−1)(−1+y)=8

(y

2

−1)=8

⇒y=±3

The no : are −4,−1,2 or 2,−1,−4

Step-by-step explanation:

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