Question

the sum of three numbers in the ratio 3:6:7 is 432. Find the product of the greatest and the smallest numbers.​

Answer 1

☞GIVEN :

The sum of three numbers in the ratio 3:6:7 is 432.

☞TO FIND :

Find the product of the greatest and the smallest numbers.

☞SOLUTION :

Let 3:6:7 could be 3x, 6x, 7x.

3x + 6x + 7x = 432

16x = 432

x = 27

☞HENCE,

1. 3x = 3 * 27 = 81

2. 6x = 6 * 27 = 162

3. 7x = 7 * 27 = 189

☞THEREFORE,

Product of greatest and smallest no. is.

81 * 189 = 15,309

HOPES, IT'S HELPFUL TO YOU BRO. ☺