Question

The sum of three numbers is 123 . If the ratio between first and second numbers is2:5 and that of between second and third is 3 :4 then find the difference between second and third number

Answer 1

Solution:-

Since A:B= 2:5 and B:C= 3:4

= >> A:B:C= 6:15:20

Where A B C are first second and third numbers.

Sum = A+B+C= (6+15+20) N= 123

N= 123/41= 3

Difference between second and third = 20N-15N= 20×3-15×3= 15

And=> 15

Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Let the three numbers be a, b, and c.

Given that:

• a:b = 2:5

We can also write it as

a:b = 6:15

Alos second given condition is

b:c = 3:4

We can also write it as

b:c = 15:20

Hence from above equations

a:b:c = 6:15:20

Let us assume that a = 6x, b = 15x and c = 20x

Given sum of all the three numbers = 123

On adding all the three numbers we get,

a + b + c =123

6x + 15x + 20x =123

41x = 123

x = 3

Hence a = 18, b = 45 and c = 60.

• The difference between the second and the third number is 60 - 45 =15