Question

the sum of three numbers is 143.first number is the double of second and the third number is 1/3 of first. find the second number.​

Answer 1

Answer:

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Step-by-step explanation:

Let’s call the 3 numbers a,b and c . a is the first, and c is the third, meaning c=4a . a is 5 less than the 2nd number, b . Which means a=b−5 .

We also know  a+b+c=149 .

We can replace  c  with  4a , meaning we are left with  5a+b=149 .

We can now replace  a  with  b−5 , giving:

5(b−5)+b=149  

5b−25+b=149  

6b=149+25  

6b=174  

b=29  

We have one of our numbers, it should be easy to get the other two. We now know that:

a=29−5  

a=24  

And from that:

c=4∗24  

c=96  

So we have our culprits! Sure enough,  24+29+96=149

Answer 2

Answer:

Let the digit in units place be x.

Let the digit in units place be x. Then, digit in ten's place =3x

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31x

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13x

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88⇒x=2

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88⇒x=2So, the original number is 31x or 31×2=62.

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88⇒x=2So, the original number is 31x or 31×2=62.On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88⇒x=2So, the original number is 31x or 31×2=62.On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.So, the resulting number we get is 26.

Let the digit in units place be x. Then, digit in ten's place =3xSo, original number =10(3x)+x=31xOn interchanging the digits, new number =10x+3x=13xAccording to the given condition,31x+13x=88⇒44x=88⇒x=2So, the original number is 31x or 31×2=62.On the other hand, if we consider the digit in ten's place as x, then the digit in unit's place will be 3x.So, the resulting number we get is 26.Here, both answers are correct, as 26+62=88.

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