Question

the sum of three numbers is 25 the second number is twice the first and the third exceeds the second by 5 find the numbers ​

Answer 1

Answer:

the sum of three numbers is 25 the second number is twice the first and the third exceeds the second by 5 find the numbers

are

Step-by-step explanation:

Let The first no: be x.

Acc. to question.

Second no:=2x

Third no: =2x+5

And.

x+2x+5+2x=25

→5x=25-5

→5x=20

→x=20/5=4

So. First no: =4

second no:=2×4=8

third no: =8+5=13

Checking...

4+8+13=25.

So

4,8,13 are the Three number's you are looking for.

Hope it Helps...

Answer 2

Given:

1. The sum of 3 numbers is 25.
2. The 2nd number is twice the 1st number.
3. The 3rd number exceeds the 2nd number by 5.

Find:

The 3 Numbers.

Solution:

Let us denote the 1st number by a variable x.

Then the 2nd number is 2x and the 3rd number is 2x + 5. [From given]

It is also given that their sum is 25.

So, by adding all 3 numbers in their variable form we get:

(x) + (2x) + (2x + 5) = 25.

5x + 5 = 25.

5x = 25 - 5.

5x = 20.

x = 20/5.

x = 4.

Therefore, the 3 numbers are:

x = 4.

2x = 2(4) = 8.

2x + 5 = 2(4) + 5 = 8 + 5 = 13.