Question

The sum of three numbers is 25. The second number is twice the first and the third exceeds the second by 5. Find the numbers.

Answer 1

Let The first no: be x.

Acc. to question.
Second no:=2x
Third no: =2x+5

And.

x+2x+5+2x=25
→5x=25-5
→5x=20
→x=20/5=4

So. First no: =4
second no:=2×4=8
third no: =8+5=13

Checking...
4+8+13=25.

So

4,8,13 are the Three number's you are looking for.

Hope it Helps...
Regards,
Leukonov.

Answer 2

let first number be x

second is 2x

third is 2x+5

so,

x+2x+2x+5=25

5x+5=25

5x=20

hence, x=4

second number =8

third number=13