Question

the sum of three numbers is 57 if twice the first is 6 less than the second number and the second number is 10 more than the third number find the number​

Answer 1

Step-by-step explanation:

Let 3rd no be x

now 2nd no be x+10

also 1st no be x+10-6=x+4

total sum is 57 (as per given data)

a/q

x+10+x+4+x=57

3x+14=57

3x=57-14

x=43/3

x=use your calculator now