Question

the sum of three numbers is 58 the second number is three times of two fifth of the first number and the third number is 6 less than the first number find the three numbers ​

Answer 1

Let the first number be x.

Second number = 3(2x/5)

Third number = x - 6.

Now,

x + (6x/5) + x - 6 = 58

2x + (6x/5) - 6 = 58

x = 20

Then:

Second number = 24

Third number = 14

Therefore numbers are:

20,24 and 14.

Answer 2

$\huge\underline\purple{\sf Answer}$

$- the \: first \: number \: be \: = x \\ \\ - the \: second \: number = 3( \frac{2x}{5} ) \\ \\ - third \: number = x - 6$

NOW ::

$...x = (6x \div 5) + x - 6 = 58 \\ \\ ...2x + (6x \div 5) = 58 \\ \\ ...x = 20.$

✴Now substitute x=20.in second and third number.

$second \: number= 3(2 \times 20 \div 5) = 3 \times 40 \div 5 \\ \\ = 24 \\ \\ \\ third \: number = 20 - 6 \\ \\ = 14$

➡The first number is =20.

➡The second number =24

➡The third number =14

✴The three consecutive numbers are 20,,24,,14

$\huge\underline\pink{\sf Thank you }$