Question

the sum of three numbers is 87. If twice the first number is 6 less than the second and the second number is 10 more than the third , find the numbers.​

Answer 1

Answer:

First no. = 17, Second no. = 40, Third no. = 30

Step-by-step explanation:

Let us assume the first number as variable x.

Then, Second number - 2x + 6

Then, Third number -  Second Number - 10 ⇒ (2x + 6) - 10 ⇒ 2x - 4

Now let us substitute this in the equation that was first given,

Sum of all three number = 87

First + second + third = 87

(Substituting the values)

(x) + (2x + 6) + (2x - 4) = 87

x + 2x  + 6 + 2x - 4 = 87

Getting like terms together,

2x + 2x + x + 6 - 4 = 87

5x + 2 = 87

5x = 87 - 2

5x = 85

x = 85/5 = 17

x = 17

Now let us find the real values,

First number = x = 17

Second number = 2x + 6 = 2 × 17 + 6 = 34 + 6 = 40

Third number = 2x - 4 = 2 × 17 - 4 = 34 - 4 = 30

There is your answer,

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