Question

the sum of three numbers is 98.if the ratio of the first to second is 2:3 and that of the second to third is 5:8, then what is the second number?

A.20
B.48
C.30
D.58

please answer in detail

Answer 1

let the first number be n1.let the second number be n2.let the third number be n3.given that n1/n2=2/3.given that n2/n3=5/8 .given that n1+n2+n3=98. consider n1/n2 =2/3 write this as 3n1=2n2.so n1=2/3 n2 . consider n2/n3=58.write this as 8n2=5n3.so n3=8/5 n2.n1+n2+n3 =98- 2/3n2+n2+8/5n2=98 =n2 (10+1+24)=98=n2=30 is answer

Answer 2

Answer:

Step-by-step explanation:

Let the three numbers be x, y and z.

Sum of the numbers is 98.

x + y + z = 98………………(i)

The ratio of the first to the second is 2/3.

x/y = 2/3.

x = 2/3 × y.

x = 2y/3.

The ratio of the second to the third is 5/8.

y/z = 5/8.

z/y = 8/5.

z = 8/5 × y.

z = 8y/5.

Put the value of x = 2y/3 and z = 8y/5 in (i).

2y/3 + y + 8y/5 = 98

49y/15 = 98.

49y = 98 × 15.

49y = 1470.

y = 1470/49.

y = 30 .

Therefore, the second number is 30.

Answer: (c)