Question

the sum of three terms of an AP is 21 and the product of the first and third term exceeds the second term by 6. Find the three terms.






please help me by doing this sum in step by step manner​

Answer 1

Answer:

Step-by-step explanation:

Let the three terms of AP are a,a+d,a+2d.

Now,

As per the question ,

a+a+d+a+2d = 3a+3d = 21

i.e. a+d = 7 or, d= 7-a.

Now,

a(a+2d)-(a+d) = 6

a{a+2(7-a)}-7 = 6

a{a+14-2a}=13

a{14-a} =13

14a-a^2 =13

a^2 -14a +13 = 0

By applying quadratic formula, you will get

a= 13, 1.

d will be 7-a i.e. -6 ,6.

Now, there will be two AP

13,7, 1 and 1,7,13.