Question

The sum of three terms of an ap is 21 and the product of the first and third is exceed the 2nd term by 6 find all three tearm

Answer 1

3a=21
a=7
now
(a-d)(a+d) = a+6
a^2-d^2 = a+6
put value of a
49 - d^2 = 13
d=6
ap is 1 , 7 ,13

Answer 2

all three terms = 13,7,1 ...