Question

The sum of thrice the first and the second is 142 and four times the first exceeds the second by 138, then find the numbers.

Answer 1

let the numbers be x and y
3x + y = 142. -(1)
ATQ - 4x - y = 138 -(2)

compare (1) and (2)
3x + y = 142
y= 142-3x

putting this value in equation 2

4x - (142-3x) = 138
4x -142 +3x = 138
7x -142 = 138
7x = 138+142
7x = 280
x = 280/7. = 40
x= 40
y= 142 - 3x
142 - 3× 40
142 - 120
22

x= 40 and y= 22
I hope this answer helps you toooooo

Answer 2

Answer:

3x+y=142

4x_y=138

3x+y=142

4x_y=138

=7x=280

x=280÷7

=40

3x+y=142

3(40)+y=142

120+y=142

y=142_120

y=22