The sum of twice a number and 6 less than the number is the same as the difference between -38 and the number. What is the number?
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Answer:
let that number be x
so, 2x + x-6=-38-x
2x=. -38+6-x-x
2x=. -32-2x
32=-2x-2x
32=-4x
x= -32/4
x=-8
therefore, required number is -8
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