Question

The sum of twice the first number and thrice the second number is 492 and four times the first number exceeds seven times the second number by 2 then the numbers are​

Answer 1

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Given :  two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92           ........(1)

⇒4x−7y=2            ........(2)

multiply the first equation by 2 , and subtract eqn (1) from eqn (2) 

4x+6y=184

−(4x−7y=2) , we get

⇒13y=182

⇒y=13182=14

Put y=14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=250=25

∴x=25 and y=14

Answer 2

Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.

To find : the two numbers

Let x and y be the two numbers required.

According to the question :

⇒2x+3y=92 ........(1)

⇒4x−7y=2 ........(2)

multiply the first equation by 2

4x+6y=184

subtract eqn (1) from eqn (2)

4x+6y − (4x−7y)= 184–2 , we get

⇒13y = 182

⇒y = 13182 = 14

Put y = 14 in (1)

2x+3y=92

⇒2x+3×14=92

⇒2x=92−42=50

∴x=250=25

∴x = 25 and y = 14

Explanation:

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