The sum of twice the first number, Second number and thrice the thing number is 5 If thrice the second number is survtracted from the sum of the first number and twice the third number we get 10. If the third number is subtracted from the sum of thrice the first twice the second, we get 1. Find the numbers. Please give me answer with complete steps
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Step-by-step explanation:
Let us assume, the two numbers are x and y.
Given:
3x + y = 142 ------------1
And also given:
4x – y = 138
y = 4x – 138 --------------2
Substitute the value of y from eqn 2 in eqn 1
3x + 4x – 138 = 142
7x - 138 = 142
7x = 142 + 138
7x = 280
x = 40
Therefore, y = (4 * 40) – 138 = 22
The two numbers are 40 and 22
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