Question

the sum of twice the number and the second number is 61 the second number is 17 less than four times the first

Answer 1

Step-by-step explanation:

Let the first number be x.

twice the number=2x

let the second number=y

According to the given condition,

2x +y=61

four times the first number=4x

17 less than 4x=4x-17

y=4x -17

put value of y in 2x+y=61

2x+4x-17=61

6x-17=61

6x=61+17

6x=78

x=78/6

x=13