Question

The sum of two angles of a triangle is 80⁰ and their difference is 20⁰. Find the angles of triangle.

a . <A=50⁰,<B=30⁰,<C=100⁰

b. <A=40⁰,<B=50⁰,<C=100⁰

c. <A=80⁰,<B=20⁰,<C=80⁰

d. none of these

​

Answer 1

Answer:

X+y = 80

X-y =20

X=80-y

80-y-y =20

-2y = 20-80

-2y= - 60

Y = 30

X=50

50+30+other angle =180

Angle = 100