Question

The sum of two angles of a triangle is 95 and their difference is 25 .find all the three angles of a triangle.

Answer 1

$let \: the \: angles \: be \: a \: b \: and \: c \: \\ by \: angle \: sum \: propety \: of \: triangle \\ a + b + c = 180 \\ given \: in \: question \: \\ a + b = 95 \\ a - b = 25 \\ add \\ 2a = 120 \\ a = 60 \\ b = 35 \\ hence \: c = 180 - 95 = 85$
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Answer 2

Let the first two angles be x and y .
Then , x + y = 95 -(1)
also , x - y = 25 -(2)
putting x = 95 -y in (2)
95 - y -y = 25
2y = 70
y = 35
On putting y= 35° in (1) , we get , x = 60°
Now in the triangle , sum of all angles =180°
therefore, third angle = 180° - (60°+35°)= 85°
Hence , the required angles are 60°, 35° and 85°

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