The sum of two consecutive even integer is 46 . Find the integer
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Let one consecutive even integer be x and the other would be (x+2)
the sum is 46 .So,
x+(x+2)=46
2x+2=46
2x=46-2
2x=44
x=44/2
x=22
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Answer:
Let the first even integer =X
And second even integer=(X+2)
X+(X+2)=46
2x+2=46
2x=46-2
2x=44
X=44/2
#x=22
So, First even integer X=22
And second even integer (X+2) =(22+2)
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