Question

the sum of two consecutive even integers is 58 find the two integers​

Answer 1

Answer:

• let the first integer be x

• let the second integer be x + 2

• sum of x + x + 2 = 58

➡️ x + x + 2 = 58

➡️ 2x = 58 - 2

➡️ 2x = 56

➡️ x = 56/2

➡️ x = 28

first integer = 28

Other integer = 28+2

= 30

Answer 2

Answer :-

• The numbers are 28 and 30.

Step-by-step explanation ::

To Find :-

• The two integers

Solution :-

Given that,

• The sum of two consecutive even integers = 58

Assumption:

Let us assume one number as x and the other number as x + 2,

Therefore,

• x + ( x + 2 ) = 58

⟹ x + x + 2 = 58

⟹ 2x + 2 = 58

Transposing 2 from L.H.S to R.H.S,

⟹ 2x = 58 - 2

Subtracting 2 from 58,

⟹ 2x = 56

Transposing 2 from L.H.S to R.H.S

⟹ x = 56/2

Dividing 56 and 2 with 2

⟹ x = 28

Hence, the value of x is 28.

Therefore, the numbers are :-

• The number which we assumed as x

⟹ x

⟹ 28

• The number which we assumed as x + 2

⟹ x + 2

⟹ 28 + 2

⟹ 30

Hence, the numbers are 28 and 30.

Now, Verification

• x + ( x + 2 ) = 58

We have,

• L.H.S = x + ( x + 2 )
• R.H.S = 58

By putting the value of the numbers,

⟹ x + ( x + 2 )

⟹ 28 + 30

⟹ 58

Hence,

• L.H.S = 58
• R.H.S = 58

Hence, Verified!