the sum of two consecutive even numbers is 23 more than the average of these two numbers. what is the second number ?
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Answered by
9
Hey!!!!
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let the consecutive even integers be x and x + 2.
Their Average => (x + x + 2)/2
=> Average = x + 1
ATQ,
=> x + x + 2 - 23 = x + 1
=> 2x - 21 = x + 1
=> x = 22
Thus the other number is 24.
Thus the numbers are 22 and 24
_____________
Hope this helps ✌️
Good Night :-)
___________
let the consecutive even integers be x and x + 2.
Their Average => (x + x + 2)/2
=> Average = x + 1
ATQ,
=> x + x + 2 - 23 = x + 1
=> 2x - 21 = x + 1
=> x = 22
Thus the other number is 24.
Thus the numbers are 22 and 24
_____________
Hope this helps ✌️
Good Night :-)
Answered by
5
let the numbers be x and x+2
x+x+2-(x+x+2/2)=23
2x+2-x-1=23
x+1=23
x=22
the second number is x+2=24
x+x+2-(x+x+2/2)=23
2x+2-x-1=23
x+1=23
x=22
the second number is x+2=24
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