The sum of two consecutive integers is 161. Find the consecutive integers.
Answers
Answered by
8
Let the two consecutive integers be (x) and (x+1)
Given that,
The sum of the two consecutive integers =161
= (X )+ (X+1) = 161
= X+X+1 = 161
= 2X+1 = 161
= 2X = 161-1
= 2X = 160
= X = 160/2
= X = 80
=> (x) = 80
=> (x+1)= (80+1) = 81
Therefore the two consecutive integers are 80 and 81.....
Hope!!! it helps you...
Answered by
29
Answer:
two consecutive integers are : 80 and 81.
Step-by-step explanation:
Let the two consecutive integers be :
- n
- n+1
Given that, their sum is 161,
=> n + n + 1 = 161
=> 2n + 1 = 161
=> 2n = 161 - 1
=> 2n = 160
=> n = 160/2
=> n = 80
Therefore, two consecutive integers are : 80 and 81.
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