Question

the sum of two consecutive multiples of 16
is 208. find these multiples

Answer 1

Hi there!
Here's the answer:

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Let the first multiple be x
& the other is x+1

Given,
Sum of these consecutive multiples of 16 = 208

=> 16x + 16(x+1) = 208
=> 16(2x+1) = 208
=> 2x+1 = 208/16
=> 2x+1 = 13
=> 2x = 12
=> x = 6


•°• The Required Multiplies of 16 are 6 & 7


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Hope it helps