Question

the sum of two consecutive multiples of 3 is 69.the ratio of numbers is

Answer 1

Let x , ( x + 3 ) are consecutive

multiples of 3 ,

sum of these two numbers = 69

x + x + 3 = 69

=> 2x + 3 = 69

=> 2x = 69 - 3

=> 2x = 66

=> x = 33

Therefore ,

Two numbers are ,

x = 33 ,

x + 3 = 33 + 3 = 36

ratio = 33 : 36

= 11 : 12

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Answer 2

one multiple be 3x
consecutive multiple be 3x+3
according to problem
3x+(3x+3)=69
3x+3x+3=69
6x+3=69
6x=66
x=11
one multiple 3x =3(11)=33
consecutive multiple be 3x+3=3(11)+3=33+3=36