Question

the sum of two consecutive multiples of 4 is 68.Find the numbers.

Answer 1

Hi Friend !!!

Here is ur answer !!!

Let the numbers be 4x and 4x+4

4x+4x+4 = 68

8x+4 = 68

8x = 68-4

x = 64/8

x = 8

4x = 4(8)

= 32

4x+4 = 32+4 = 36


Hope it helps u : )

= 64

Answer 2

let us assume, one of that multiple is 4x and the other one is 4(x+1)

Now, 4x + 4(x+1) = 68
or, 4x + 4x + 4 = 68
or, 8x = 68 - 4 = 64
or, x = 64/8 = 8

therefore, the numbers are
4x = 4*8 = 32
4*(8+1) = 36