Question

the sum of two consecutive multiples of 5 is 75. find the number ​

Answer 1

Answer:

Step-by-step explanation:

let the two consecutive number be 5x, 5(x+1)

according to question

5x + 5(x+1) = 75

5x + 5x + 5 = 75

10x = 75-5

10x = 70

x = 7

the number are

5x =  5(7)= 35

5(x+1) = 5(7+1) =5(8)= 40

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Answer 2

Answer:

Required two numbers are 35 and 40

Step-by-step explanation:

Given,sum of two consecutive multiples of 5 is 75.

Let two consecutive multiples of 5 be 5x and (5x+5)

According to question,

$5x + (5x + 5) = 75 \\ 10x + 5 = 75 \\ 10x = 75 - 5 \\ 10x = 70 \\ x = \frac{70}{10} \\ x = 7$

So,two numbers are (7×5) = 35 and (35+5) = 40

This is a problem of Algebra.

Some important Algebra formulas:

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2} \\ {(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2} \\ {(x + y)}^{3} = {x}^{3} + 3 {x}^{2} y + 3x {y}^{2} + {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3x {y}^{2} - {y}^{3} \\ {x}^{3} + {y}^{3} = {(x + y)}^{3} - 3xy(x + y) \\ {x}^{3} - {y}^{3} = {(x - y)}^{3} + 3xy(x - y) \\ {x}^{2} - {y}^{2} = (x + y)(x - y) \\ {x}^{2} + {y}^{2} = {(x - y)}^{2} + 2xy \\ {x}^{2} - {y}^{2} = {(x + y)}^{2} - 2xy \\ {x}^{3} - {y}^{3} = (x - y)( {x}^{2} + xy + {y}^{2} ) \\ {x}^{3} + {y}^{3} = (x + y)( {x}^{2} - xy + {y}^{2} )$

Two more important Algebra problem:

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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