the sum of two consecutive multiples of 5 is 85. find them.
Answers
Answered by
0
Answer:
let the multiples be x and x+5
so,
x+x+5 = 85
2x+5 = 85
2x = 85-5
2x = 80
x = 80/2
x = 40
therfore, the multiples are 40 and 45
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Answered by
0
Answer:
Let the
three consecutive multiples of 8 be 8x, 8(x + 1), 8(x
+ 2).
Sum
of these numbers =
8x + 8(x
+ 1) + 8(x
+ 2) = 888
8(x
+ x + 1 +
x + 2) = 888
8(3x
+ 3) = 888
On dividing both sides
by 8, we obtain
3x
+ 3 = 111
On transposing 3 to
R.H.S, we obtain
3x
= 111 − 3
3x
= 108
On dividing both sides
by 3, we obtain
x
= 36
First
multiple = 8x = 8 × 36 = 288
Second
multiple = 8(x + 1) = 8 × (36 + 1) = 8 × 37
= 296
Third
multiple = 8(x + 2) = 8 × (36 + 2) = 8 × 38
= 304
Hence, the required
numbers are 288, 296, and 304.
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